Question

Два мальчика вышли в 10 часов в противоположном направлении из одного дома и остановились через 8 мин. На каком расстоянии друг от друга они оказались, если шли со скоростями 80 м/мин и 60 м/мин

Answer 1

80/8=10м -прошел первый
60/8=15/2=7,5 - прошел второй
10-7,5=2,5м

Answer 2

Problem Analysis

Two boys start walking in opposite directions from the same house at 10:00. They stop after 8 minutes. The boys have different walking speeds: one walks at 80 m/min and the other at 60 m/min. We need to determine the distance between them when they stop.

Solution

To find the distance between the two boys when they stop, we can calculate the total distance each boy covers in 8 minutes and then add those distances together.

Let's calculate the distance covered by each boy:

Boy 1 (walking at 80 m/min): - Speed: 80 m/min - Time: 8 minutes - Distance covered: 80 m/min * 8 min = 640 meters Boy 2 (walking at 60 m/min): - Speed: 60 m/min - Time: 8 minutes - Distance covered: 60 m/min * 8 min = 480 meters Now, let's add the distances covered by both boys to find the total distance between them:

Total distance = Distance covered by Boy 1 + Distance covered by Boy 2 = 640 meters + 480 meters = 1120 meters

Therefore, the two boys are 1120 meters apart when they stop walking.

Answer

The two boys are 1120 meters apart when they stop walking.

Explanation

When the two boys start walking in opposite directions from the same house at 10:00, they walk for 8 minutes. Boy 1 walks at a speed of 80 m/min and covers a distance of 640 meters in 8 minutes. Boy 2 walks at a speed of 60 m/min and covers a distance of 480 meters in 8 minutes. When we add these distances together, we get a total distance of 1120 meters between the two boys when they stop walking.