Question

Ответить срочно 1)6|x|-2|x|=35-16|x| 2)29|x|-13=-22|x| ДАЁ ЗА ЭТО 26 БАЛОВ СРОЧНО!!!!!

Answer 1

1) 6IxI-2IxI=35-16IxI
6IxI-2IxI+16IxI=35
20IxI=35
IxI=1.75
x=+-1.75
2) 29|x|-13=-22|x|
29|x|+22|x|=13
51|x|=13
|x|=1/3
x=+-1/3

Answer 2

Solving the Equations

To solve the given equations, let's start with the first equation: 6|x| - 2|x| = 35 - 16|x|.

First, we'll combine like terms to simplify the equation: 6|x| - 2|x| = 35 - 16|x| 4|x| = 35 - 16|x|

Now, we'll isolate the absolute value term on one side of the equation: 4|x| + 16|x| = 35 20|x| = 35

Next, we'll solve for |x| by dividing both sides by 20: |x| = 35/20 |x| = 1.75

So, the solution for the absolute value equation 6|x| - 2|x| = 35 - 16|x| is |x| = 1.75.

Moving on to the second equation: 29|x| - 13 = -22|x| + 26.

We'll start by isolating the absolute value term on one side of the equation: 29|x| + 22|x| = 13 + 26 51|x| = 39

Now, we'll solve for |x| by dividing both sides by 51: |x| = 39/51 |x| = 0.7647

So, the solution for the absolute value equation 29|x| - 13 = -22|x| + 26 is |x| = 0.7647.

Therefore, the solutions for the given equations are: 1. |x| = 1.75 2. |x| = 0.7647