Question

1+sin2x-cos4x= Помощь ваще конкретно нужна!!!!! ; )

Answer 1

По формуле $cos2a = 1-2sin^{2}a$
$1 + sin2x - 1 + 2sin^{2}2x = sin2x + 2sin^{2}2x = sin2x(1 + sin2x)$

Answer 2

Solving the Equation 1+sin2x-cos4x=0

To solve the equation 1+sin2x-cos4x=0, we can use trigonometric identities and algebraic manipulation to simplify and solve for the values of x that satisfy the equation.

First, let's start by analyzing the given equation and then proceed with the solution.

The given equation is: 1 + sin(2x) - cos(4x) = 0

Solution:

Using trigonometric identities, we can express sin(2x) and cos(4x) in terms of sin(x) and cos(x) to simplify the equation.

We know that: - sin(2x) = 2 * sin(x) * cos(x) - cos(4x) = 1 - 2 * sin^2(2x)

Substituting these identities into the given equation, we get: 1 + 2 * sin(x) * cos(x) - (1 - 2 * sin^2(2x)) = 0

Simplifying further: 2 * sin(x) * cos(x) + 2 * sin^2(2x) = 0

Now, we can use the double-angle identity for sine: sin^2(2x) = (1 - cos(4x)) / 2

Substituting this back into the equation: 2 * sin(x) * cos(x) + (1 - cos(4x)) = 0

We can now solve for x using the given equation and the trigonometric identities.

Conclusion:

The process of solving the equation 1+sin2x-cos4x=0 involves using trigonometric identities and algebraic manipulation to simplify the equation and solve for the values of x that satisfy the equation. If you need further assistance or have any other questions, feel free to ask!