Question

Из двух городов ,расстояние между которыми равно 112 км ,навстречу друг другу одновременно выехали мотоциклист и велосипедист.Найдите скорость каждого из них, если они встретились через 1,6 ч после выезда и скорость мотоциклиста в 4 раза больше скорости велосипедиста.

Answer 1

Обозначим скорост велосипедиста через х
тогда 112:(х+4х)=1,6
5х=112:1,6
5х=70
х=14 км/ч - скорость вело.
4х=4*14=56 км/ч - скорсть мото.

Answer 2

Problem Analysis

We are given that a motorcyclist and a cyclist start simultaneously from two cities that are 112 km apart. After 1.6 hours, they meet each other. We need to find the speed of each of them, given that the speed of the motorcyclist is 4 times the speed of the cyclist.

Solution

Let's assume the speed of the cyclist is x km/h. Since the speed of the motorcyclist is 4 times the speed of the cyclist, the speed of the motorcyclist is 4x km/h.

We can use the formula distance = speed × time to solve this problem.

The distance traveled by the cyclist in 1.6 hours is x × 1.6 km.

The distance traveled by the motorcyclist in 1.6 hours is 4x × 1.6 km.

Since they meet each other after 1.6 hours, the sum of the distances traveled by both of them should be equal to the total distance between the cities, which is 112 km.

So, we can write the equation:

x × 1.6 + 4x × 1.6 = 112

Simplifying the equation:

1.6x + 6.4x = 112

8x = 112

Dividing both sides of the equation by 8:

x = 14

Therefore, the speed of the cyclist is 14 km/h and the speed of the motorcyclist is 4 × 14 = 56 km/h.

Answer

The speed of the cyclist is 14 km/h and the speed of the motorcyclist is 56 km/h.