Question

Из двух пунктов, расстояние между которыми 7 км.500 м. одновременно в одном направлении вышел пешеход со скоростью 6 км в час и выехал автобус. Определите скорость автобуса, если он догнал пешехода через 15 мин.

Answer 1

15мин это 0,25  часа
7  км  =700 и +500м=7,5 
1) 6*0,25=1,5 км - прошёл пешеход
2)7,5+1,5=9 км - проехал автобус
3)9:0,25=36 км/ч - скорость автобуса

Answer 2

Problem Analysis

We are given that there are two points with a distance of 7 km 500 m between them. A pedestrian starts walking from one point with a speed of 6 km/h, and at the same time, a bus starts moving from the same point. We need to determine the speed of the bus if it catches up to the pedestrian after 15 minutes.

Solution

To solve this problem, we can use the formula: speed = distance / time.

Let's calculate the distance covered by the pedestrian in 15 minutes: - The pedestrian's speed is given as 6 km/h, which means the pedestrian covers 6 km in 1 hour. - In 15 minutes (0.25 hours), the pedestrian covers (6 km/h) * (0.25 hours) = 1.5 km.

Now, let's calculate the remaining distance between the bus and the pedestrian after 15 minutes: - The total distance between the two points is given as 7 km 500 m. - The distance covered by the pedestrian in 15 minutes is 1.5 km. - Therefore, the remaining distance between the bus and the pedestrian is (7 km 500 m) - (1.5 km) = 6 km.

Since the bus catches up to the pedestrian after 15 minutes, the bus covers the remaining distance of 6 km in the same time. Therefore, the speed of the bus is: - Speed = Distance / Time = 6 km / 0.25 hours = 24 km/h.

Answer

The speed of the bus is 24 km/h.