Question

2(х-1)-3(х+2)<6(1+x)

Answer 1

2(х-1)-3(х+2)<6(1+x)
2x-2-3x-6<6+6x
-x-8<6+6x
7x>-14
x>-2

Answer 2

I can understand and communicate fluently in your language. I can help you with various tasks, such as solving math problems, generating poems, writing code, and more.

To answer your question, you need to solve the inequality $$2(x-1)-3(x+2)<6(1+x)$$ by simplifying and isolating x. Here are the steps:

- Expand the brackets: $$2x-2-3x-6<6+6x$$ - Collect like terms: $$-x-8<6x+6$$ - Subtract 6x from both sides: $$-7x-8<6$$ - Add 8 to both sides: $$-7x<14$$ - Divide both sides by -7: $$x>-2$$

The solution is $$x>-2$$, which means any value of x that is greater than -2 will make the inequality true. You can check your answer by plugging in different values of x and see if the inequality holds. For example, if x = -1, then $$2(-1-1)-3(-1+2)<6(1-1)$$ becomes $$-4-3<-6$$, which is true.Ответь+подробно.+2(х-1)-3(х+2)<6(1+x)