Question

Дамир ехал час по одной дороге и два часа по другой покаким дорогам он ездил если всего проехал 190км пути

Answer 1

Если учесть, что скорость оставалась постоянной, то 
$S_{1} = Vt_{1}$
$S_{2} = Vt_{2}$
$S = S_{1}+S_{2}$
$190 = V*1+V*2=3V$
$V=63 \frac{1}{3}$ км/ч
$S_{1} = 63 \frac{1}{3}$ км
$S_{2} = 126 \frac{2}{3}$ км

Answer 2

Solution:

To solve this problem, we can use the concept of average speed and the formula: average speed = total distance / total time.

Given: - Distance traveled: 190 km - Time traveled on the first road: 1 hour - Time traveled on the second road: 2 hours

Calculations:

Let's denote the speed on the first road as x km/h and the speed on the second road as y km/h.

We can set up the following equations based on the given information: 1. x * 1 = distance on the first road 2. y * 2 = distance on the second road 3. x + y = total distance / total time

Using these equations, we can solve for the values of x and y.

Solution:

Let's solve for the values of x and y using the given information and the equations above.

1. From the first equation: x = distance on the first road / 1 = distance on the first road 2. From the second equation: y = distance on the second road / 2 = distance on the second road / 2

Now, we can use the third equation to solve for x + y: x + y = 190 / (1 + 2) = 190 / 3 = 63.33 km/h

So, the average speed of Damir's travel was 63.33 km/h.

Conclusion:

Damir traveled at an average speed of 63.33 km/h.