Question

велосипедист и мотоцыклист выехали одновремено навстречу дрг другу из двух посёлках.Велосипедист ехал со скоростью 12 км/ч,а мотоциклист-40 км/ч1)найди скорость сближения велосипедиста и мотоцыклиста.2)на сколько км велосипедист и мотоцыклистприблизятся друг к другу за 2 ч

Answer 1

Скорость сближения равна 40-12=28км/ч
Соответственно, через 2 часа они сблизятся на 56 км/ч 28x2=56

Answer 2

Problem Statement

A cyclist and a motorcyclist set off simultaneously towards each other from two different villages. The cyclist is traveling at a speed of 12 km/h, while the motorcyclist is traveling at a speed of 40 km/h. We need to find: 1) The rate at which the cyclist and the motorcyclist are approaching each other. 2) The distance by which the cyclist and the motorcyclist will approach each other in 2 hours.

Solution

To solve this problem, we can use the formula: distance = speed × time.

1) The rate at which the cyclist and the motorcyclist are approaching each other can be found by adding their speeds together. Therefore, the rate of approach is 12 km/h + 40 km/h = 52 km/h.

2) To find the distance by which the cyclist and the motorcyclist will approach each other in 2 hours, we can multiply the rate of approach by the time. Therefore, the distance is 52 km/h × 2 h = 104 km.

So, the answers to the given questions are: 1) The rate of approach is 52 km/h. 2) The distance by which the cyclist and the motorcyclist will approach each other in 2 hours is 104 km.

Please note that the sources provided did not directly answer the questions. The solution is derived from basic mathematical principles.