Question

Б)-2/3*(6/7-y)+(2/7+y) в)-(y+1/8)+3/4*(2+y) г)1/9*(3/5-x)-(x-1/15) Помогите решить.Срочно!

Answer 1

$- \frac{2}{3} ( \frac{6}{7} -y)+(\frac{2}{7} +y)=- \frac{4}{7} +\frac{2}{3}y+\frac{2}{7} +y=- \frac{2}{7} +\frac{5}{3}y \\\ -(y+ \frac{1}{8} )+ \frac{3}{4} (2+y)=-y-\frac{1}{8}+ \frac{3}{2}+\frac{3}{4}y=\frac{11}{8}-\frac{1}{4}y \\\ \frac{1}{9}( \frac{3}{5}-x)-(x- \frac{1}{15})= \frac{1}{15}- \frac{1}{9}x-x+ \frac{1}{15}= \frac{2}{15}- \frac{10}{9}x$

Answer 2

1) = (-4/7+2у/3 +2/7 +у) = (-12+14у + 6 +21у) / 21 = (35у +6)/21= 35у/21 + 2/7
2)= -у-1/8+6/4+3у/4 = (-8у -1+12 +6у)/8 = (11-2у)/8 =(1/8)(11-2у)
3) = 1/15 -х/9 -х +1/15 = (3 -5х -45х + 3)/45 = (6-50х)/45