
Задача:два мотоциклиста ехали навстречу друг другу.Скорость одного из них 48.5 км,и она меньше
скорости другого на 5.3 км.Через 0.6 ч они встретились.Какое расстояние было между мотоциклистами в начале пути.

Ответы на вопрос

Путь который они проехали за 0,6 час равен = 102,3 * 0,6 =61,38 = 61,4 км
Ответ : В начале пути расстояние между мотоциклистами было 61,4 км



Problem Analysis
We have two motorcyclists traveling towards each other. The speed of one motorcyclist is 48.5 km/h, which is 5.3 km/h less than the speed of the other motorcyclist. After 0.6 hours, they meet. We need to find the initial distance between the motorcyclists.Solution
Let's assume the speed of the faster motorcyclist is x km/h. According to the problem, the speed of the slower motorcyclist is x - 5.3 km/h.We know that distance = speed × time. After 0.6 hours, the faster motorcyclist has traveled a distance of x × 0.6 km, and the slower motorcyclist has traveled a distance of (x - 5.3) × 0.6 km.
Since they meet, the sum of their distances traveled must be equal to the initial distance between them. Therefore, we can write the equation:
x × 0.6 + (x - 5.3) × 0.6 = initial distance
Simplifying the equation, we get:
0.6x + 0.6x - 3.18 = initial distance
Combining like terms, we have:
1.2x - 3.18 = initial distance
To find the initial distance, we need to solve for x. We can do this by substituting the given information into the equation.
From the problem, we know that the speed of one motorcyclist is 48.5 km/h, which is 5.3 km/h less than the speed of the other motorcyclist. Therefore, we can write the equation:
48.5 = x - 5.3
Simplifying the equation, we get:
x = 48.5 + 5.3
Solving for x, we find:
x = 53.8
Now, we can substitute the value of x into the equation for the initial distance:
1.2(53.8) - 3.18 = initial distance
Simplifying the equation, we get:
64.56 - 3.18 = initial distance
Therefore, the initial distance between the motorcyclists was 61.38 km.
Answer
The initial distance between the two motorcyclists was 61.38 km.

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