Question

С двух концов одной канатной дороги одновременно навстречу друг другу двинулись два вагончика. Скорость вагончиков 6 м/ с. Длина канатной дороги 2160 м. Через сколько минут вагончики встретятся? Какое расстояние будет между вагончиками через 15 с после встречи?

Answer 1

1)6+6=12
2)2160/12=180 сек.= 3 мин.
3)12*15= 180 метров.

Answer 2

1) 2160/2=1080 (м) проходит каждыв вагон до встречи2) 1080/6=180 (с) время до встречи3) 180/60=3 (мин) время до встречи вагончиков4) 15*6*2=180( м) расстояние между вагончиками через 15 секунд

Answer 3

Problem Analysis

We have two cable cars moving towards each other on a cableway. The speed of each cable car is 6 m/s, and the length of the cableway is 2160 m. We need to determine how long it will take for the cable cars to meet and the distance between them 15 seconds after they meet.

Calculation

To find the time it takes for the cable cars to meet, we can use the formula:

Time = Distance / Relative Speed

The relative speed of the cable cars is the sum of their individual speeds, which is 6 m/s + 6 m/s = 12 m/s.

Substituting the values into the formula, we get:

Time = 2160 m / 12 m/s = 180 seconds

Therefore, it will take 180 seconds for the cable cars to meet.

To find the distance between the cable cars 15 seconds after they meet, we can use the formula:

Distance = Speed * Time

The speed of each cable car is 6 m/s, and the time is 15 seconds.

Substituting the values into the formula, we get:

Distance = 6 m/s * 15 s = 90 meters

Therefore, the distance between the cable cars 15 seconds after they meet will be 90 meters.

Answer

The cable cars will meet after 180 seconds, and the distance between them 15 seconds after they meet will be 90 meters.