Question

В каждом из 2 вагонов трамвая было одинаковое число пассажиров. после остановки в 1 вагоне стало на 20 пассажиров меньше , а во 2 на 10 и число пассажиров в первом вагоне составило 5\6 числа пассажиров во 2 вагоне . сколько пассажиров было в каждом вагоне до остановки

Answer 1

После остановки во втором вагоне осталось х
после остановки осталось в первом вагоне 5\6х
было до остановки во втором вагоне х+10
было до остановки в первом вагоне 5/6х+20
составим уравнение
х+10=5\5х+20
х-5/6х=20-10
1/6х=10
х=10:1/6
х=60 осталось во втором вагоне после остановки
60+10=70 было во втором до остановки
70*5/6=50 осталось в первом после остановки
50+20=70 было в первом до остановки
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Answer 2

Problem Analysis

We are given that there are two tram cars with an equal number of passengers. After a stop, the number of passengers in the first car decreased by 20, while the number of passengers in the second car decreased by 10. Additionally, the number of passengers in the first car is 5/6 of the number of passengers in the second car. We need to determine the number of passengers in each car before the stop.

Solution

Let's assume the number of passengers in each car before the stop is x.

According to the given information: - After the stop, the number of passengers in the first car decreased by 20, so the number of passengers in the first car is x - 20. - After the stop, the number of passengers in the second car decreased by 10, so the number of passengers in the second car is x - 10. - The number of passengers in the first car is 5/6 of the number of passengers in the second car, so we can write the equation: (x - 20) = (5/6)(x - 10).

To solve this equation, we can multiply both sides by 6 to eliminate the fraction: 6(x - 20) = 5(x - 10)

Expanding and simplifying the equation: 6x - 120 = 5x - 50 x = 70

Therefore, the number of passengers in each car before the stop was 70.

Answer

Before the stop, there were 70 passengers in each tram car.