Question

Две машинистки выполнили работу за 4 дня. Если бы работала одна из них, она выполнила бы эту работу за 6 дней . Какую часть работы выполняла каждая машинистки за день?

Answer 1

Одна из них за один день делает 1/6 часть работы
Вторая из них за один день делает 1/х часть работы

Вместе они за один день делют 1/4 часть работы

Следовательно :

1/6 +1/x = 1/4

 х = 12

Ответ : Первая делает 1/6 часть работы за день.Вторая за один день делает 1/12 часть работы

Answer 2

Solution:

Let's denote the amount of work one of the machinists can do in one day as x and the amount of work the other machinist can do in one day as y.

Given: - Two machinists completed the work in 4 days. - If one of them worked alone, she would have completed the work in 6 days.

We can set up the following system of equations to solve for x and y: 1. 4x + 4y = 1 (Both machinists working together completed the work in 4 days, which is equivalent to 1 whole job) 2. 6x = 1 (If one machinist worked alone, she would have completed the work in 6 days, which is equivalent to 1 whole job)

Calculation:

Solving the system of equations: 1. From equation 2, we find that x = 1/6. 2. Substituting x = 1/6 into equation 1, we get 4(1/6) + 4y = 1. Solving for y, we find that y = 1/6.

So, each machinist completes 1/6 of the work in one day.

Therefore, each machinist completes 1/6 of the work per day.

This solution is based on the given information and the calculations performed.