Question

Два мюмзика летали в мове с одинаковой скоростью. Первый пролетел 600км второй 780км .Первый был в пути 3ч меньше. Сколько времени был в пути каждый мюмзик

Answer 1

600/3=200км/ч (летел первый)
так как скорость одинаковая ,то 780/200=3,9 ч. (был в пути 2-ой)

Answer 2

Problem Analysis

We are given that two "mumziks" flew in the air at the same speed. The first mumzik flew a distance of 600 km, while the second mumzik flew a distance of 780 km. Additionally, the first mumzik spent 3 hours less in the air than the second mumzik. We need to determine the amount of time each mumzik spent in the air.

Solution

Let's assume that both mumziks flew at a constant speed of v km/h. We can use the formula `distance = speed × time` to find the time each mumzik spent in the air.

For the first mumzik: - Distance = 600 km - Speed = v km/h - Time = t1 hours (to be determined)

For the second mumzik: - Distance = 780 km - Speed = v km/h - Time = t2 hours (to be determined)

We can set up the following equations based on the given information:

Equation 1: 600 = v × t1 Equation 2: 780 = v × t2 Equation 3: t1 = t2 - 3

To solve this system of equations, we can substitute Equation 3 into Equation 1:

600 = v × (t2 - 3)

Simplifying Equation 4, we get:

600 = v × t2 - 3v

Now, let's solve for v in terms of t2:

600 + 3v = v × t2 3v = v × t2 - 600 3v = v(t2 - 600)

Dividing both sides by v:

3 = t2 - 600

Adding 600 to both sides:

t2 = 603

Now that we have the value of t2, we can substitute it back into Equation 3 to find t1:

t1 = t2 - 3 t1 = 603 - 3 t1 = 600

Therefore, the first mumzik was in the air for 600 hours, and the second mumzik was in the air for 603 hours.

Answer: The first mumzik was in the air for 600 hours, and the second mumzik was in the air for 603 hours.