Question

Первый велосипедист догонял второго, причем расстояние между ними уменьшалось каждый час на 2 целых 3 четвёртых км. С какой скоростью ехал первый велосипедист, если второй ехал со скоростью 12 целых 1 вторая км/ч?

Answer 1

Для удобства решения переведём простые дроби в десятичные:
2 целых 3/4=2,75;         12целых1/2=12,5
скорость второго велосипедиста = 12,5 км/час,
первый велосипедист ехал с большей скоростью, чем второй на 2,75км/час, т.к. расстояние между ними уменьшалось на 2,75км.
Значит  12,5+2,75=15,25 (км/час) - скорость первого велосипедиста

Answer 2

Problem Analysis

We are given that the first cyclist is catching up to the second cyclist, and the distance between them decreases by 2 and 3/4 km every hour. We need to determine the speed of the first cyclist, given that the second cyclist is traveling at a speed of 12 and 1/5 km/h.

Solution

Let's assume the speed of the first cyclist is x km/h.

In one hour, the first cyclist covers a distance of x km, and the second cyclist covers a distance of 12 and 1/5 km.

According to the problem, the distance between them decreases by 2 and 3/4 km every hour. So, the equation can be formed as:

x - (12 and 1/5) = 2 and 3/4

To solve this equation, we need to convert the mixed fractions into improper fractions:

x - (61/5) = 11/4

Now, let's solve for x:

x = (61/5) + (11/4)

To add these fractions, we need to find a common denominator:

x = (244/20) + (55/20) = 299/20

Therefore, the speed of the first cyclist is 299/20 km/h.

Answer

The first cyclist was traveling at a speed of 299/20 km/h.

Explanation

The problem states that the first cyclist is catching up to the second cyclist, and the distance between them decreases by 2 and 3/4 km every hour. By setting up an equation and solving it, we find that the speed of the first cyclist is 299/20 km/h.