Question

Инженер приходил на станцию в одно и то же время, и в это де время за ним приезжала машина с завода. Инженер приехал на станцию на 55мин раньше и сразу же пошел навстречу машине. В итоге он приехал на завод на 10мин раньше. Какова Vмаш, если Vинж=5км/ч

Answer 1

Путь пройден инж (55/60)*5
Путь пройд. Маш это скорость Маш. * 10/60 скор Маш рпаа (55*5)/10 -27,5км/ч

Answer 2

Calculating the Speed of the Car

To calculate the speed of the car, we can use the formula: distance = speed × time

Given: - Speed of the engineer (Vинж) = 5 km/h - The engineer arrived at the station 55 minutes earlier than usual and reached the factory 10 minutes earlier than usual.

Let's denote: - Vмаш as the speed of the car - t as the usual time it takes for the car to arrive after the engineer

The engineer covers the distance to the factory in the usual time minus 10 minutes, and the car covers the same distance in the usual time. The engineer walks for 55 minutes, and the car drives for the usual time minus 55 minutes.

Using the formula, we can set up the equation: 5 * (t - 10) = Vмаш * (t - 55)

Solving for Vмаш: Vмаш = 5 * (t - 10) / (t - 55)

To find the value of Vмаш, we need to know the usual time it takes for the car to arrive after the engineer.

Conclusion

The speed of the car (Vмаш) can be calculated using the formula Vмаш = 5 * (t - 10) / (t - 55), where t is the usual time it takes for the car to arrive after the engineer.