Question

Витя ждал гостей на день рождения. Вокруг стола поставили несколько табуретов и несколько стульев. У каждого табурета было по 3 ножки, а у каждого стула - по 4. Ребята заняли все стулья и табуреты, и оказалось,, что всех ножек - у стульев, табуретов и ребят -49. Сколько всего ребят было за столом

Answer 1

9*2=18ног у ребят

49-18=31 ножек у стульев и табурет

4*4=16ножек у 4 стульев

5*3=15 ножек у 5 табуреток

16+15=31 ножек всего у табуреток и стульев

18+31=49

Ответ 9 ребят

Answer 2

Solution:

To solve this problem, we can use a system of equations to represent the given information and then solve for the number of children at the table.

Let's denote: - t as the number of stools - s as the number of chairs - c as the number of children

We are given the following information: 1. Each stool has 3 legs, and each chair has 4 legs. 2. The total number of legs of the stools, chairs, and children is 49.

We can express this information in the form of equations: 1. 3t + 4s + 2c = 49 (since each child has 2 legs) 2. t + s + c = 16 (since the total number of stools, chairs, and children is 16)

We can solve these equations to find the value of c.

Calculation:

Let's solve the system of equations to find the value of c.

First, we'll express t in terms of c using the second equation: t = 16 - s - c

Substitute the value of t into the first equation: 3(16 - s - c) + 4s + 2c = 49 48 - 3s - 3c + 4s + 2c = 49 48 + s - c = 49 s - c = 1 s = c + 1

Now, substitute the value of s into the second equation: 16 = t + (c + 1) + c 16 = t + 2c + 1 t = 15 - 2c

Substitute the values of t and s into the first equation: 3(15 - 2c) + 4(c + 1) + 2c = 49 45 - 6c + 4 + 2c + 2c = 49 45 + 4 = 49 49 = 49

The equation 49 = 49 is always true, which means that the number of children at the table can be any value. Therefore, there is no unique solution for the number of children at the table.

Conclusion:

The total number of children at the table cannot be determined uniquely based on the given information.