Question

Из Цветочного и Солнечного городов выехали одновременно навстречу друг другу Знайка и Незнайка. Знайка ехал со скоростью 56 км/ч, что составляло одну 8/11 скорости движения Незнайки.Через сколько часов после начала движения они встретятся,если расстояние между городами ровно 532км?

Answer 1

Скорость Знайки:  v₁ = 56 км/ч
Скорость Незнайки: v₂ = v₁ : 8/11 = 56 : 8/11 = 56 * 11/8 = 77 (км/ч)

Скорость сближения: v = v₁+v₂ = 56+77 = 133 (км/ч)

Время, через которое они встретятся: t = S/v = 532/133 = 4 (ч.)

Ответ: через 4 часа.

Answer 2

56 :8 ×11=77 км/ч
56+77=133 км/ч
532:133=4 ч
Ответ: Они встретятся через 4 часа

Answer 3

Problem Analysis

We are given that Znaika and Neznaika start traveling towards each other from the cities of "Цветочный" and "Солнечный" respectively. Znaika is traveling at a speed of 56 km/h, which is 8/11 of Neznaika's speed. We need to determine how many hours it will take for them to meet if the distance between the cities is 532 km.

Solution

Let's assume that it takes x hours for Znaika and Neznaika to meet. During this time, Znaika would have traveled a distance of 56x km, and Neznaika would have traveled a distance of y km.

We know that the ratio of Znaika's speed to Neznaika's speed is 8/11. Therefore, we can write the equation:

56/8 = y/11

Simplifying the equation, we get:

y = (56 * 11) / 8

Now, we can substitute the value of y into the equation for the total distance traveled:

56x + y = 532

Substituting the value of y, we get:

56x + (56 * 11) / 8 = 532

Simplifying the equation, we can solve for x:

56x + 616/8 = 532

Multiplying both sides of the equation by 8 to eliminate the fraction:

448x + 616 = 4256

Subtracting 616 from both sides of the equation:

448x = 3640

Dividing both sides of the equation by 448:

x = 3640 / 448

Calculating the value of x, we find:

x ≈ 8.125

Therefore, it will take approximately 8.125 hours for Znaika and Neznaika to meet.

Answer

Znaika and Neznaika will meet approximately 8.125 hours after they start traveling towards each other.