Question

Решите задачу с решением : В каждом из двух вагонов трамвая было одинаковое число пассажиров. После остановки в первом вагоне стало на 20 пассажиров меньше,а во втором- на 10 и число пассажиров в первом вагоне составило пять шестых числа пассажиров во втором вагоне.Сколько пассажиров было в каждом вагоне до остановки?

Answer 1

Пусть х - число пассажиров в каждом вагоне, тогда (х-20) - стало в первом вагоне, (х-10) - во втором.
Составим уравнение:
(х-20) =(х-10)*5/6
Раскрываем скобки:
х-20=(5х-50)/6
6х-120=5х-50
х=70

Ответ: В каждом вагоне было 70 пассажиров. 

Answer 2

Problem Analysis

We are given that there are two tram cars with an equal number of passengers. After a stop, the number of passengers in the first car decreased by 20, and the number of passengers in the second car decreased by 10. Additionally, the number of passengers in the first car is five-sixths of the number of passengers in the second car. We need to find the number of passengers in each car before the stop.

Solution

Let's assume the number of passengers in each car before the stop is x.

According to the given information: - After the stop, the number of passengers in the first car decreased by 20, so the number of passengers in the first car is x - 20. - After the stop, the number of passengers in the second car decreased by 10, so the number of passengers in the second car is x - 10. - The number of passengers in the first car is five-sixths of the number of passengers in the second car, so we can write the equation: (x - 20) = (5/6)(x - 10).

To solve this equation, we can multiply both sides by 6 to eliminate the fraction: 6(x - 20) = 5(x - 10).

Expanding and simplifying the equation: 6x - 120 = 5x - 50.

Moving all the terms to one side: 6x - 5x = -50 + 120.

Simplifying further: x = 70.

Therefore, there were 70 passengers in each car before the stop.

Answer

There were 70 passengers in each tram car before the stop.