Question

Упростите. Покажите методику решения пожалуйста!

Answer 1

$\displaystyle \sqrt{21-2 \sqrt{21+2 \sqrt{19-6 \sqrt{2} } } } =\sqrt{21-2\sqrt{21+2\sqrt{(3\sqrt{2}-1)^2}}}=\\ \\ \\ =\sqrt{21-2\sqrt{21+2|3\sqrt{2}-1|}}=\sqrt{21-2\sqrt{19+6\sqrt{2}}}=\\ \\ \\ =\sqrt{21-2\sqrt{(3\sqrt{2}+1)^2}}=\sqrt{21-2|3\sqrt{2}+1|}=\sqrt{19-6\sqrt{2}}=3\sqrt{2}-1$

Answer 2

Methodology for Solving the Problem

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