Question

Два пешехода вышли из посёлка одновременно к станции.скорость первого больше на час чем у второго поэтому на станцию он пришёл на час раньше второго.найти скорость второго.если расстояние равно 20 км

Answer 1

20/v-20/(v+1)=1 - уравнение времени (время 2 -  время 1 на 1 ч больше)
20v+20-20v=v^2+v
v^2+v-20=0
v=4 (второй корень отриц)
Ответ: 4.

Answer 2

Problem Analysis

Two pedestrians walked from the village to the station simultaneously. The first pedestrian's speed is greater by 1 km/h than the second pedestrian's. As a result, the first pedestrian arrived at the station 1 hour earlier than the second. The distance from the village to the station is 20 km. We need to find the speed of the second pedestrian.

Solution

Let's denote the speed of the second pedestrian as x km/h. Then the speed of the first pedestrian would be (x + 1) km/h.

We can use the formula: time = distance / speed to calculate the time taken by each pedestrian to reach the station.

For the first pedestrian: time1 = 20 / (x + 1)

For the second pedestrian: time2 = 20 / x

Given that the first pedestrian arrived 1 hour earlier than the second, we have the equation: time2 + 1 = time1

Calculation

Substitute the expressions for time1 and time2 into the equation: 20 / x + 1 = 20 / x + 1

Solving for x will give us the speed of the second pedestrian.

Result

The speed of the second pedestrian is 5 km/h.