Question

Два поезда одновременно вышли от двух станций и встретились через 3 3/2 ч после отправления. Один из поездов проходит все расстояние между станциями за 5 1/2 ч. За сколько часов пройдет это расстояние второй поезд

Answer 1

Пусть расстояние между станциями S
Тогда скорость первого v1=S/t, где t=5 1/2=11/2 часа, v1=2s/11
Скорость сближения v1+v2
Время встречи S/(v1+v2)=3 2/3=11/3
v1+v2=s/11/3=3S/11
v2=3S/11-v1=3S/11-2s/11=S/11
t2=11 часов
Ответ 11 часов проходит это расстояние второй поезд

Answer 2

Problem Analysis

We have two trains that leave two different stations simultaneously and meet each other after 3 3/2 hours. One of the trains covers the entire distance between the stations in 5 1/2 hours. We need to find out how long it will take for the second train to cover the same distance.

Solution

Let's assume the speed of the first train is x km/h and the speed of the second train is y km/h. We know that the first train covers the distance between the stations in 5 1/2 hours, so we can write the equation:

Distance = Speed × Time

For the first train: Distance = x × 5 1/2

For the second train: Distance = y × Time

Since both trains meet after 3 3/2 hours, the distance covered by the first train is the same as the distance covered by the second train. Therefore, we can equate the two equations:

x × 5 1/2 = y × (3 3/2)

Now, let's solve this equation to find the value of y.

Calculation

To solve the equation, we need to convert the mixed fractions into improper fractions:

x × (11/2) = y × (7/2)

Now, we can cancel out the common factors:

11x = 7y

To find the value of y, we can divide both sides of the equation by 7:

y = (11x)/7

So, the second train will cover the distance between the stations in (11x)/7 hours.

Answer

The second train will cover the distance between the stations in (11x)/7 hours, where x is the speed of the first train in km/h.

Note: The specific value of x is not provided in the question, so we cannot determine the exact time it will take for the second train to cover the distance without that information.