
Велосипедист выехал с постоянной скоростью из города А в город В, расстояние между которыми равно
112 км. Отдохнув, он отправился обратно в А, увеличив скорость на 9 км/ч. По пути он сделал остановку на 4 часа, в результате чего затратил на обратный путь столько же времени, сколько на путь из А в В. Найдите скорость велосипедиста на пути из А в В.

Ответы на вопрос

112/х=112/(х+9)+4
Ответ: 12км/ч.



Problem Analysis
A cyclist travels from city A to city B at a constant speed. After resting, the cyclist returns from city B to city A, increasing their speed by 9 km/h. During the return journey, the cyclist makes a 4-hour stop, which results in the same amount of time spent on the return journey as on the journey from A to B. We need to find the cyclist's speed on the journey from A to B.
Solution
Let's assume the cyclist's speed on the journey from A to B is x km/h.
We know that the distance between city A and city B is 112 km.
The time taken for the journey from A to B can be calculated using the formula: time = distance / speed.
Therefore, the time taken for the journey from A to B is 112 / x hours.
On the return journey, the cyclist increases their speed by 9 km/h, so the speed is now x + 9 km/h.
The time taken for the return journey is the same as the time taken for the journey from A to B, plus the 4-hour stop.
Therefore, the time taken for the return journey is 112 / (x + 9) + 4 hours.
Since the time taken for the return journey is the same as the time taken for the journey from A to B, we can set up the following equation:
112 / x = 112 / (x + 9) + 4
To solve this equation, we can cross-multiply and simplify:
112(x + 9) = 112x + 4(x + 9)
Simplifying further:
112x + 1008 = 112x + 4x + 36
The 112x terms cancel out, and we are left with:
1008 = 4x + 36
Subtracting 36 from both sides:
972 = 4x
Dividing both sides by 4:
x = 243
Therefore, the cyclist's speed on the journey from A to B is 243 km/h.
Answer
The cyclist's speed on the journey from city A to city B is 243 km/h.


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