Question

Брошены одновременно монета и игральная кость. Найти вероятность того, что мо- нета упала гербом вверх, а на игральной кости не появится цифра 4.

Answer 1

Вероятность того, что монета упала гербом вверх 0,5
Вероятность того, что игральная кость упала не цифрой 4 вверх равна 5/6
Вероятность того, что эти события произойдут одновременно 0,5*5/6=5/12

Answer 2

Problem Analysis

To find the probability of getting a coin with heads up and a dice without the number 4, we need to consider the possible outcomes for each event and calculate the probability of the desired outcome.

Coin Toss

When tossing a fair coin, there are two possible outcomes: heads (H) or tails (T). Since we want the coin to land with heads up, there is only one favorable outcome.

Dice Roll

When rolling a fair six-sided dice, there are six possible outcomes: 1, 2, 3, 4, 5, or 6. Since we don't want the number 4 to appear, there are five unfavorable outcomes: 1, 2, 3, 5, and 6.

Probability Calculation

To calculate the probability of both events happening simultaneously, we multiply the probabilities of each event.

The probability of getting heads on the coin is 1/2 (one favorable outcome out of two possible outcomes).

The probability of not getting the number 4 on the dice is 5/6 (five unfavorable outcomes out of six possible outcomes).

Therefore, the probability of getting heads on the coin and not getting the number 4 on the dice is:

P(coin heads and dice not 4) = (1/2) * (5/6) = 5/12.

So, the probability is 5/12.

Please note that the above calculation assumes that the coin and dice are fair and unbiased.

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