Question

(20+3*(x-3))-8=41 ПОМОГИТЕ решить уравнение пожалуйста!!!!!

Answer 1

(20+3*(x-3))-8=41
(20+3*(x-3))=41+8
3*(x-3)=49-20
3*(x-3)=29
(x-3)=29/3
x=29/3+3
x=12 2/3

Answer 2

10х-3+14х-4=8-15+22х; 2х+3-5х-11=7+13-2х; -3х+2х=20-3+11; -х=28;х=-28;
4х-22х=-7+3+4;
х=0;

Answer 3

To solve the equation (20 + 3*(x-3)) - 8 = 41, we can follow these steps:

Step 1: Simplify the equation by applying the distributive property: (20 + 3x - 9) - 8 = 41

Step 2: Combine like terms: 20 + 3x - 9 - 8 = 41

Step 3: Simplify further: 3x + 3 = 41

Step 4: Subtract 3 from both sides of the equation: 3x = 38

Step 5: Divide both sides of the equation by 3 to solve for x: x = 38/3

Therefore, the solution to the equation (20 + 3*(x-3)) - 8 = 41 is x = 38/3.