Question

Моторная лодка прошла против течения 24 км и вернулась обратно, затратив на обратный путь на 20 минут меньше, чем при движении против течения. Найдите скорость лодки в неподвижной воде, если скорость течения равна 3 км/ч

Answer 1

Х скорость в неподвижной воде (собственная)
х+3 скорость по течению.
х-3 против
20мин=1/3часа
24/(х-3)-24/(х+3)=1/3
72х+216-72х+216=х²-9
432=х²-9
х²=441
х=21км/час собственная скорость в стоячей воде

Answer 2

Calculating the Speed of the Boat in Still Water

To find the speed of the boat in still water, we can use the following approach:

Let's denote: - Speed of the boat in still water as b (in km/h) - Speed of the current as c (in km/h)

Given: - Distance traveled against the current = 24 km - Time taken to return against the current = 20 minutes less than the time taken to travel against the current

We can use the formula: - Speed = Distance / Time

First, let's calculate the time taken to travel against the current and the time taken to return against the current.

The time taken to travel against the current is given by: 24 / (b - c)

The time taken to return against the current is given by: 24 / (b + c)

According to the given information, the time taken to return against the current is 20 minutes less than the time taken to travel against the current. We can express this as an equation: 24 / (b - c) - 24 / (b + c) = 20/60

Solving this equation will give us the value of b.

Let's proceed with the calculation.