Question

Решите задачу В двух карманах было28 орехов причем в левом кармане в 3 раза больше чем в правом .Сколько орехов было в каждом кармане

Answer 1

В одном кармане -X орехов, во втором- 3Х орехов
Х+3Х=28
4Х=28
Х=28/4
Х=7
2)7*3=21
Ответ: в первом кармане 7 орехов, во втором 21 орех

Answer 2

В левом 21 в правом 7.

Answer 3

Solving the Problem

To solve the problem, we can use algebra to represent the number of nuts in each pocket. Let's denote the number of nuts in the right pocket as x and the number of nuts in the left pocket as 3x. We know that the total number of nuts is 28, so we can write the equation:

x + 3x = 28

Solving for x will give us the number of nuts in the right pocket, and then we can find the number of nuts in the left pocket.

Calculation

Using the equation x + 3x = 28: - 4x = 28 - x = 7

So, there were 7 nuts in the right pocket and 3 * 7 = 21 nuts in the left pocket.

Therefore, there were 7 nuts in the right pocket and 21 nuts in the left pocket.

This information is based on the provided search results: - Source Title: ' 28 , ... - Mail.ru' - Source Title: ' / vivat2.okis.ru'