Question

Дан прямоугольник со сторонами 5 см и 9 см. Найдите его периметр и площадь. Нарисуйте квадрат с таким же периметром и найдите его площадь.

Answer 1

Периметр прямоугольника P=2(a+b)
P=2(5+9)=28 cм

Площадь прямоугольника S=a·b
S=5·9=45 см²

Периметр квадрата P=4a
P= 28 cм
a= P:4
a=28:4=7см

Площадь квадрата S=a²
S=7²=49 cм²

Answer 2

S=5*9=45СМ КВАДРАТНЫХ-ПРЯМОУГОЛЬНИКА
Р=5*2+9*2=10+18=28СМ-ПРЯМОУГОЛЬНИКА
КВАДРАТ, У КОТОРОГО ПЕРИМЕТР РАВЕН 28 СМ, ИМЕЕТ СТОРОНУ ДЛИНОЙ 7 СМ.
S=7*7=49СМ КВАДРАТНЫХ-КВАДРАТА

Answer 3

Perimeter and Area of a Rectangle

To find the perimeter and area of a rectangle with sides measuring 5 cm and 9 cm, we can use the following formulas:

- Perimeter (P) = 2 * (length + width) - Area (A) = length * width

Let's calculate the perimeter and area of the given rectangle:

1. Perimeter: - Length (a) = 9 cm - Width (b) = 5 cm - P = 2 * (a + b) = 2 * (9 + 5) = 2 * 14 = 28 cm.

Therefore, the perimeter of the rectangle is 28 cm.

2. Area: - Length (a) = 9 cm - Width (b) = 5 cm - A = a * b = 9 * 5 = 45 cm².

Therefore, the area of the rectangle is 45 cm².

Square with the Same Perimeter

To draw a square with the same perimeter as the given rectangle, we need to find the side length of the square. Since the perimeter of the rectangle is 28 cm, the perimeter of the square should also be 28 cm.

Let's calculate the side length and area of the square:

- Perimeter of the square = 28 cm.

To find the side length (s) of the square, we can use the formula:

- Perimeter (P) = 4 * s

Solving for s:

- 28 = 4 * s - s = 28 / 4 = 7 cm

Therefore, the side length of the square is 7 cm.

To find the area of the square, we can use the formula:

- Area (A) = s²

Substituting the value of s:

- A = 7² = 49 cm²

Therefore, the area of the square is 49 cm².

In summary: - The perimeter of the given rectangle is 28 cm. - The area of the given rectangle is 45 cm². - The side length of the square with the same perimeter is 7 cm. - The area of the square is 49 cm².

I hope this helps! Let me know if you have any further questions.