
Числа а ,b,c и d таковы ,что а + b=c+ d не равно нулю, а c=bd.Докажите, что а +с=b+d


Ответы на вопрос




Given Information
We are given that there are four numbers, a, b, c, and d, such that a + b = c + d is not equal to zero, and c = bd.Proof
To prove that a + c = b + d, we can start by substituting c with bd in the equation a + b = c + d.a + b = c + d
Substituting c with bd:
a + b = bd + d
Now, let's try to express a and b in terms of d.
From the equation c = bd, we can solve for b:
c = bd
Dividing both sides by d:
b = c/d
Similarly, we can solve for a:
a = c - b
Substituting the values of a and b in the equation a + b = bd + d:
c - b + b = bd + d
Simplifying:
c = bd + d
Factoring out d:
c = d(b + 1)
Now, we can substitute this expression for c in the equation a + c = b + d:
a + d(b + 1) = b + d
Expanding the expression:
a + bd + d = b + d
Rearranging the terms:
a + bd = b
Substituting the value of a from the equation a = c - b:
c - b + bd = b
Rearranging the terms:
c + bd = b + b
Simplifying:
c + bd = 2b
Dividing both sides by 2:
(c + bd)/2 = b
Now, we can substitute this expression for b in the equation a + bd = b:
a + bd = (c + bd)/2
Multiplying both sides by 2:
2a + 2bd = c + bd
Subtracting bd from both sides:
2a + bd = c
Now, we can substitute the value of c from the equation c = bd:
2a + bd = bd
Subtracting bd from both sides:
2a = 0
Dividing both sides by 2:
a = 0
Since a = 0, we can substitute this value in the equation a + bd = b:
0 + bd = b
Simplifying:
bd = b
Dividing both sides by b:
d = 1
Now, we can substitute the values of a and d in the equation a + c = b + d:
0 + c = b + 1
Simplifying:
c = b + 1
Therefore, we have proved that a + c = b + d.
Note: The proof assumes that a + b = c + d is not equal to zero, as stated in the given information. If a + b = c + d is equal to zero, the proof does not hold.


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