Question

Два токаря должны изготовить 240 деталей.Первый токарь это задание выполняет за 5 часов . второй токарь за час обробатывает на 16 деталей меньше,чем первый . Если два токаря будут работать совместно,то за скока часов выполнять это задание?

Answer 1

240/5=48- скорость первого
48-16=32- скорость второго
48+32=80-общая скорость
240/80=3- время за которое, они выполнят вместе

Answer 2

Task Description

Two lathe operators are tasked with manufacturing 240 parts. The first operator can complete the task in 5 hours, while the second operator can process 16 fewer parts per hour than the first operator. The question is, how many hours will it take for the two operators to complete the task if they work together?

Solution

To find the solution, we need to calculate the combined productivity of both operators and then determine the time it would take to complete 240 parts at that combined productivity.

Let's start by calculating the productivity of each operator.

The first operator can complete the task in 5 hours, so their productivity is 240 parts / 5 hours = 48 parts per hour.

The second operator processes 16 fewer parts per hour than the first operator. Therefore, their productivity is 48 parts per hour - 16 parts per hour = 32 parts per hour.

To find the combined productivity of both operators, we add their individual productivities:

48 parts per hour + 32 parts per hour = 80 parts per hour.

Now, we can determine the time it would take for the two operators to complete the task if they work together. We divide the total number of parts (240) by the combined productivity (80 parts per hour):

240 parts / 80 parts per hour = 3 hours.

Therefore, if the two operators work together, it will take them 3 hours to complete the task of manufacturing 240 parts.