Question

Сколько лет мужчине если известно что он на 2 года старше всех своих четырех сыновей вмесье взятых , а также сумма возрастов двух средних сыновей составляет 20 ? Разница в возрасте между сыновьями одинаковая.

Answer 1

Думаю 42года ) 1сыну 4лет ,2ому 8, 3ему 12, 4ому 16 разница в 4года )4+8+12+16=40+2=42

Answer 2

Calculating the Man's Age and His Sons' Ages

To calculate the man's age and his sons' ages, we can use the information provided in the question and the given sum of the ages of the two middle sons.

Let's denote: - The man's age as M - The ages of his four sons as S1, S2, S3, and S4

We know that the man is 2 years older than all of his four sons combined, so we can express this as: M = S1 + S2 + S3 + S4 + 2

We are also given that the sum of the ages of the two middle sons is 20, which can be expressed as: (S2 + S3) = 20

Given that the difference in age between the sons is the same, we can express the ages of the sons as: S1, S2, S3, S4 = M - 2 - 4x, M - 2 - 2x, M - 2 + 2x, M - 2 + 4x where x is the constant difference in age between the sons.

Solving for the Man's Age and His Sons' Ages

To solve for the man's age and his sons' ages, we can use the information provided and the equations derived above. We'll start by finding the value of x and then use it to calculate the ages.

Given that (S2 + S3) = 20, we can substitute the expressions for S2 and S3 and solve for x.

(M - 2 - 2x) + (M - 2 + 2x) = 20

Solving this equation will give us the value of x. Once we have x, we can use it to find the man's age and his sons' ages.

Let's proceed with solving the equation to find the value of x.