Question

С одной станции одновременно в противоположных напралениях отправились два поезда,и через 12 часов расстояние между ними было 1584км.Скорость одного поезда 8км/ч больше скорости другого.Найдите скорость каждого поезда.

Answer 1

Х-скорость второго поезда
х+8-скорость первого
12х+(х+8)*12=1584
12х+12х+96=1584
24х=1584-96
х=1488/24
х=62 км/ч-скорость второго поезда
62+8=70 км/ч-скорость первого поезда

Answer 2

Problem Analysis

We are given that two trains start simultaneously from the same station in opposite directions. After 12 hours, the distance between them is 1584 km. We are also told that the speed of one train is 8 km/h greater than the speed of the other train. We need to find the speed of each train.

Solution

Let's assume the speed of the slower train is x km/h. Then the speed of the faster train will be x + 8 km/h.

We know that distance = speed × time. After 12 hours, the slower train will have traveled a distance of 12x km, and the faster train will have traveled a distance of 12(x + 8) km.

According to the problem, the distance between the two trains after 12 hours is 1584 km. So we can set up the following equation:

12x + 12(x + 8) = 1584

Simplifying the equation:

12x + 12x + 96 = 1584

24x + 96 = 1584

24x = 1488

x = 62

Therefore, the speed of the slower train is 62 km/h, and the speed of the faster train is 70 km/h.

Answer

The speed of the slower train is 62 km/h, and the speed of the faster train is 70 km/h.