Question

1354. 1) y=f(x), где f(x)=9x+2 Найдите значение функции: а) f(0); f(-2); f(1/3); f(a-1)

Answer 1

F (0)=9×0+2=0+2=2
f (-2)=9×(-2)+2=-18+2=-16
f (1/3)=9×(1/3)+2=3+2=5
f (a-1)=9×(a-1)+2=9a-9+2=9a-7

Answer 2

а) f(0) = 9*0 + 2 = 2 б) f(-2) = 9*(-2) + 2 = -18 + 2 = -16 в) f(1/3) = 9*(1/3) + 2 = 3 + 2 = 5 г) f(a-1) = 9*(a-1) + 2 = 9a - 9 + 2 = 9a - 7