Question

На одной чаше весов лежит арбуз и стоят гири общей массой 6кг. а на другой арбуз и гири массой 3кг. когда оба арбуза положили на одну чашу весов,то на другую понадобилось для равновесия поставить гири общей массы17кг.опредилите массу каждого арбуза

Answer 1

Х- кг -1-й арбуз
у - 2-й арбуз
Система уравнений:
х+6=у+3
х+у=17
Выразим  х через у в первом уравнении
х=у+3-6=у-3
Подставляем во второе уравнение у-3+у=17   2у=17+3    2у=20   у=10кг - второй арбуз
х=10-3= 7кг


Попробуй так:
х- кг -1-й арбуз
х+3 - 2-й арбуз
х+(х+3)=17
2х+3=17
2х=17-3
2х=14
х=7 кг - 1-й арбуз
7+3=10- второй

Answer 2

Problem Analysis

We have two scenarios with a balance scale: 1. In the first scenario, an watermelon and weights with a total mass of 6 kg are on one side, and an watermelon and weights with a mass of 3 kg are on the other side. 2. In the second scenario, both watermelons are placed on one side, and weights with a total mass of 17 kg are needed on the other side to achieve balance.

We need to determine the mass of each watermelon.

Solution

Let's assume the mass of the first watermelon is x kg and the mass of the second watermelon is y kg.

In the first scenario, the equation can be written as: x + 6 = y + 3

In the second scenario, the equation can be written as: x + y = 17

We can solve these two equations simultaneously to find the values of x and y.

Solving the Equations

Let's solve the equations using the substitution method.

From the first equation, we can rewrite it as: x = y + 3 - 6 x = y - 3

Substituting this value of x into the second equation, we get: (y - 3) + y = 17 2y - 3 = 17 2y = 17 + 3 2y = 20 y = 20 / 2 y = 10

Substituting the value of y back into the first equation, we get: x = 10 - 3 x = 7

Answer

Therefore, the mass of the first watermelon is 7 kg and the mass of the second watermelon is 10 kg.

Please let me know if you need any further assistance!