Question

В двух карманах было 28 орехов,причем в левом кармане в 3 раза больше,чем в правом.Сколько орехов было в каждом кармане?

Answer 1

Составим уравнение:
за х берем сколько орехов в правом кармане, тогда:
1)х + 3х = 28
4х = 28
х = 28:4
х = 7 (орехов) - в правом кармане
2)7 * 3 = 21 (орехов) - в левом кармане

Answer 2

X - карман1
28=x+3x
4x=28
x=7
7*3=21
ответ:в 1 кармане 7 орехов во 2 - 21

Answer 3

Problem Statement

The problem states that there are 28 nuts in two pockets, with three times as many nuts in the left pocket as in the right pocket. The task is to determine the number of nuts in each pocket.

Solution

Let's denote the number of nuts in the left pocket as L and the number of nuts in the right pocket as R. We are given that the total number of nuts is 28, and the number of nuts in the left pocket is three times the number of nuts in the right pocket. We can represent this information in the form of equations:

1. L + R = 28 (total number of nuts is 28) 2. L = 3R (the number of nuts in the left pocket is three times the number of nuts in the right pocket)

To solve for the number of nuts in each pocket, we can use the second equation to express L in terms of R and then substitute it into the first equation.

Calculation

Substituting L = 3R into L + R = 28: 3R + R = 28 4R = 28 R = 7

Now that we have the value of R, we can find the value of L using the equation L = 3R: L = 3 * 7 L = 21

Answer

So, there are 21 nuts in the left pocket and 7 nuts in the right pocket.