Question

Помогите пожалуйста решить дроби 54*(13/14*7/13) ,16/25/24/35, 4*1/5+4*3/7+4*1/35.Очень срочно,пожалуйста

Answer 1

54 *(13/14 * 7/13)=54 * 1/2=27

16/25 :24/35=16/25 * 35/24=(2*7)/(5*3)=14/15

4 *1/5+4 *3/7+4 *1/35=4*(1/5+1/7+1/35)=4*(7/35+5/35+1/35)=4 *15/35=4 * 3/7=12/7=1 5/7

Answer 2

Solving the Fraction Problems

Let's solve the given fraction problems step by step.

Problem 1: 54*(13/14*7/13)

To solve this, we can simplify the multiplication of fractions first and then multiply the result by 54.

First, simplify the multiplication of the fractions: \[ \frac{13}{14} \times \frac{7}{13} = \frac{91}{182} \]

Now, multiply the result by 54: \[ 54 \times \frac{91}{182} = 27 \]

So, the result of the first problem is 27.

Problem 2: 16/25/24/35

To solve this, we need to divide the first fraction by the second fraction: \[ \frac{16}{25} \div \frac{24}{35} = \frac{16}{25} \times \frac{35}{24} = \frac{560}{600} = \frac{14}{15} \]

So, the result of the second problem is 14/15.

Problem 3: 4*1/5+4*3/7+4*1/35

To solve this, we can first simplify each multiplication and then add the results together: \[ 4 \times \frac{1}{5} + 4 \times \frac{3}{7} + 4 \times \frac{1}{35} = \frac{4}{5} + \frac{12}{7} + \frac{4}{35} = \frac{28}{35} + \frac{180}{35} + \frac{4}{35} = \frac{212}{35} = 6 \]

So, the result of the third problem is 6.

Conclusion

The solutions to the given fraction problems are: 1. 54*(13/14*7/13) = 27 2. 16/25/24/35 = 14/15 3. 4*1/5+4*3/7+4*1/35 = 6

I hope this helps! If you have any more questions or need further assistance, feel free to ask.