Question

В магазин привезли арбузы. до обеда магазин продал 2/5,а после обеда 1/3 привезенных арбузов,и осталось продать 80 арбузов. сколько арбузов привезли в магазин?

Answer 1

Наверно вот:
1) 2/5 + 1/3 = 6/15 + 5/15 = 11/15 - продали
2) 1 - 11/15 = 15/15 - 11/15 = 4/15 - осталось продать
3) 4/15 = 80 арбузов. Находим целое по его части:
80 : 4 * 15 = 300 арбузов - привезли в магазин
Ответ: 300 арбузов.

Answer 2

120 арбузов привезли в магазин

Answer 3

Problem Analysis

We are given the information that a store sold 2/5 of the watermelons before lunch and 1/3 of the remaining watermelons after lunch, leaving 80 watermelons unsold. We need to determine how many watermelons were brought to the store.

Solution

Let's assume the total number of watermelons brought to the store is represented by the variable x.

According to the given information: - Before lunch, the store sold 2/5 of the watermelons, which is equal to (2/5) * x. - After lunch, the store sold 1/3 of the remaining watermelons, which is equal to (1/3) * (x - (2/5) * x).

The remaining watermelons after lunch can be calculated by subtracting the sold watermelons from the total number of watermelons: Remaining watermelons = x - [(2/5) * x + (1/3) * (x - (2/5) * x)]

According to the given information, there were 80 watermelons remaining after selling. So we can set up the equation: x - [(2/5) * x + (1/3) * (x - (2/5) * x)] = 80

Now, let's solve this equation to find the value of x.

Calculation

x - [(2/5) * x + (1/3) * (x - (2/5) * x)] = 80

Simplifying the equation: x - [(2/5) * x + (1/3) * (3/5) * x] = 80 x - [(2/5) * x + (3/15) * x] = 80 x - [(2/5) * x + (1/5) * x] = 80 x - [(2/5 + 1/5) * x] = 80 x - [(3/5) * x] = 80 (5/5) * x - (3/5) * x = 80 (2/5) * x = 80 x = (80 * 5) / 2 x = 200

Answer

Therefore, the store brought 200 watermelons to the store.

Note: The calculation above is based on the given information and the assumption that the store sold 2/5 of the watermelons before lunch and 1/3 of the remaining watermelons after lunch.