Question

Пройдя половину маршрута турист увиличел скорость 25% и поэтому пробыл часы раньше .Сколько времяни турист был внутри А В

Answer 1

S1=S2=V2*t2=6*2=12 км
t1=S1/V1=12/8=1,5 ч

VСр=(S1+S2)/(t1+t2)=24/3,5=6,86 км/ч

Answer 2

Problem Analysis

A tourist has completed half of their route and increased their speed by 25%, allowing them to arrive one hour earlier than expected. We need to determine how long the tourist spent inside points A and B.

Solution

Let's assume that the original time it would take the tourist to complete the entire route is T hours. Since the tourist increased their speed by 25%, their new speed is 125% of the original speed.

We can set up the following equation to represent the relationship between time, speed, and distance:

Distance = Speed × Time

Since the tourist has completed half of the route, the distance traveled is also half of the total distance. Therefore, we can write:

0.5 × Distance = Speed × (T - 1)

Simplifying the equation, we have:

0.5 × Distance = 1.25 × Speed × T - 1.25 × Speed

Since the tourist increased their speed by 25%, the new speed is 1.25 times the original speed. Substituting this into the equation, we get:

0.5 × Distance = 1.25 × 1.25 × Original Speed × T - 1.25 × 1.25 × Original Speed

Simplifying further, we have:

0.5 × Distance = 1.5625 × Original Speed × T - 1.5625 × Original Speed

Since the distance is constant, we can cancel it out:

0.5 = 1.5625 × T - 1.5625

Simplifying, we get:

0.5 + 1.5625 = 1.5625 × T

2.0625 = 1.5625 × T

Finally, solving for T, we have:

T = 2.0625 / 1.5625

T = 1.32

Therefore, the original time it would take the tourist to complete the entire route is 1.32 hours.

Since the tourist arrived one hour earlier, the time spent inside points A and B is:

1.32 - 1 = 0.32 hours

So, the tourist spent 0.32 hours inside points A and B.

Answer

The tourist spent 0.32 hours inside points A and B.