Question

Два поезда одновременно вышли навстречу друг другу из двух городов, расстояние между которыми 495 км через 3ч они встретились. Какова скорость каждого поезда, если известно, что скорость одного из них на 5 км/ч больше скорости другого?

Answer 1

Пусть х км/ч - скорость первого поезда, х-5 - скорость второго поезда

3х+3(х-5)=495

6х-15=495

6х=510

х=85

1)85-5=80(км/ч)

Ответ:85км/ч,80км/ч.

Answer 2

Problem Analysis

We have two trains traveling towards each other from two different cities. The distance between the cities is 495 km. After 3 hours, the trains meet each other. We need to find the speed of each train, given that the speed of one train is 5 km/h greater than the speed of the other train.

Solution

Let's assume the speed of one train is x km/h. Since the speed of the other train is 5 km/h greater, its speed will be (x + 5) km/h.

To find the speed of each train, we can use the formula: speed = distance / time.

The distance traveled by the first train in 3 hours is 3x km. The distance traveled by the second train in 3 hours is 3(x + 5) km.

Since the total distance between the cities is 495 km, we can set up the equation:

3x + 3(x + 5) = 495

Simplifying the equation:

3x + 3x + 15 = 495

6x + 15 = 495

6x = 480

x = 80

Therefore, the speed of the first train is 80 km/h and the speed of the second train is 85 km/h.

Answer

The speed of the first train is 80 km/h and the speed of the second train is 85 km/h.