Question

Для подготовки к зачету по физике девятикласснтк должен был решить 36 задач . во второй день он решил в 2 раза меньше задач. , чем в первый ,а в третий день ему осталось решить на 6 задач больше , чем в первый день . сколько задач осталось ррешить ученику в третий день .

Answer 1

Пусть х задач решил во второй день, то 2х задач в первый день, то 2х+6 в третий день. По условию: х+2х+2х+6=36. 5х=30 х=6 во второй день. 6*2+6=18 задач в третий дегь ответ:18 задач

Answer 2

Problem Analysis

To solve this problem, we need to determine the number of tasks the student had to solve on the third day. We are given the following information: - On the first day, the student solved a total of 36 tasks. - On the second day, the student solved half as many tasks as on the first day. - On the third day, the student had 6 more tasks left to solve than on the first day.

Let's use this information to find the number of tasks the student had to solve on the third day.

Solution

Let's assume that the number of tasks the student solved on the first day is x.

According to the given information: - On the second day, the student solved half as many tasks as on the first day, which is x/2 tasks. - On the third day, the student had 6 more tasks left to solve than on the first day, which is x + 6 tasks.

To find the number of tasks the student had to solve on the third day, we need to subtract the number of tasks solved on the first and second days from the total number of tasks.

The total number of tasks is given by the sum of the tasks solved on the first, second, and third days: x + (x/2) + (x + 6) = 36

Simplifying the equation: 2x + x + 2(x + 6) = 72 2x + x + 2x + 12 = 72 5x + 12 = 72 5x = 60 x = 12

Therefore, the number of tasks the student had to solve on the third day is x + 6 = 12 + 6 = 18.

Answer

The student had to solve 18 tasks on the third day.