Question

Два велосипедиста выехали навстречу друг другу из двух поселков,расстояние между которыми 76км.Через два часа они встретились.Какова скорость каждого велосипедиста,если известно ,что скорость одного из них на 3км/час меньше другого

Answer 1

Скорость одного x км/ч, скорость другого x+3 км/ч. Скорость сближения x+x+3 = 2x+3 км/ч. За 2 часа вместе проехали 76 км.
2*(2x+3) = 76
2x+3 = 38
2x = 35
x = 17,5
Скорость одного 17,5 км/ч, другого 17,5+3 = 20,5 км/ч.

Answer 2

Problem Analysis

Two cyclists start from two different villages and meet after two hours. The distance between the villages is 76 km. We need to determine the speed of each cyclist, given that one cyclist's speed is 3 km/h less than the other.

Solution

Let's assume the speed of the faster cyclist is x km/h. Then the speed of the slower cyclist will be x - 3 km/h.

We can use the formula speed = distance / time to calculate the speeds of the cyclists.

The distance covered by the faster cyclist in 2 hours is 2x km, and the distance covered by the slower cyclist in 2 hours is 2(x - 3) km.

Since they meet after 2 hours, the sum of the distances covered by both cyclists should be equal to the total distance between the villages, which is 76 km.

Therefore, we can set up the following equation:

2x + 2(x - 3) = 76

Simplifying the equation:

2x + 2x - 6 = 76

4x - 6 = 76

4x = 82

x = 20.5

The speed of the faster cyclist is 20.5 km/h, and the speed of the slower cyclist is 17.5 km/h.

Answer

The speed of the faster cyclist is 20.5 km/h, and the speed of the slower cyclist is 17.5 km/h.