Question

Когда спортсмен из 4 а класса,на последнем этапе принял эстафетную палочку,от своего товарища.Его соперник из команды 4 б класса,был впереди на 15 метров.Участник из команды 4 б класса ,бежит со скоростью пять метров в секунду,а его соперник 6 метров в секунду.Через сколько секунд второй догонит первого? И сможет ли,победить команда 4 а класса,если длина заключительного этапа составляет 90 метров?

Answer 1

скорость с которой ашник догоняет бешника 6-5=1 м/с

Он догонит его за 1*15=15 сек.

За это время он пробежит 15*6=90м.

И не победит, потому что к финишу участники придут одновременно. Будет ничья.

Answer 2

Calculation of Time and Outcome of the Race

To calculate the time it takes for the second participant to catch up to the first participant, we need to determine the relative speed between them. The second participant is ahead by 15 meters and has a speed of 6 meters per second, while the first participant has a speed of 5 meters per second.

To find the relative speed, we subtract the speed of the first participant from the speed of the second participant:

Relative speed = Speed of the second participant - Speed of the first participant = 6 m/s - 5 m/s = 1 m/s

Since the second participant is ahead by 15 meters, we can calculate the time it takes for the first participant to catch up by dividing the distance by the relative speed:

Time = Distance / Relative speed = 15 m / 1 m/s = 15 seconds

Therefore, the second participant will catch up to the first participant in 15 seconds.

Possibility of the Team from Class 4A Winning

The length of the final stage is given as 90 meters. To determine if the team from Class 4A can win, we need to compare the speeds of the two participants.

The second participant from Class 4B has a speed of 6 meters per second, while the first participant from Class 4A has a speed of 5 meters per second.

Since the second participant is faster, they will continue to increase their lead. Therefore, it is likely that the team from Class 4B will win the race.

Please note that these calculations are based on the given information and assumptions about the constant speeds of the participants throughout the race.