Question

Две сойки вылетели из гнезда и полетели в противоположных направлениях.Скорость одной 760м/мин., другой на 20м/мин. меньше.Через сколько времени между ними будет 6 км?

Answer 1

760-20=740м/мин.                              6 км.=6000 метров.

760+740=1500м./мин

6000:1500=4 минуты

ответ: 4 минуты)

вот, надеюсь помогла)

Answer 2

Problem Analysis

We are given that two jays flew out of their nest in opposite directions. The speed of one jay is 760 m/min, while the speed of the other jay is 20 m/min less. We need to determine the time it takes for the distance between them to reach 6 km.

Solution

Let's denote the speed of the faster jay as v1 and the speed of the slower jay as v2. We are given that v1 = 760 m/min and v2 = v1 - 20 m/min.

To find the time it takes for the distance between them to be 6 km, we can use the formula:

time = distance / relative speed

The relative speed between the two jays is the difference between their speeds, which is (v1 - v2).

Substituting the given values, we have:

time = 6000 m / (v1 - v2)

Now, let's calculate the time.

Calculation

The speed of the slower jay, v2, is v1 - 20 m/min.

Substituting the values, we have:

v2 = 760 m/min - 20 m/min = 740 m/min

The relative speed between the two jays is (v1 - v2).

Substituting the values, we have:

relative speed = 760 m/min - 740 m/min = 20 m/min

Now, let's calculate the time it takes for the distance between them to be 6 km.

time = 6000 m / (v1 - v2) = 6000 m / 20 m/min = 300 min

Therefore, it will take 300 minutes for the distance between the two jays to be 6 km.

Answer

The time it takes for the distance between the two jays to be 6 km is 300 minutes.