Question

Помогите под Б! Срочно! Математика!

Answer 1

$(7 \sqrt{6 \sqrt{6} }+ \sqrt[4]{216} )^{1 \frac{1}{3} }=(7 \sqrt{ \sqrt{216} } + \sqrt[4]{216} )^{4/3}=(7 \sqrt[4]{216} + \sqrt[4]{216} )^{4/3}=$
$=(8 \sqrt[4]{216} )^{4/3}=8^{4/3}* (\sqrt[4]{6^3})^{4/3} =2^4*(6^{3/4})^{4/3}=16*6=96$