Question

В коробке с квадратным дном 32 кубика, и они полностью заполнили коробку. Узнай объём коробки, если известно, что длина ребра кубика 5 см. (Я решила- объём 4000см3) 2) Какие размеры могут быть у коробки? Приведи разные варианты. (Вот с этим помогите пожалуйста.)

Answer 1

1)5×5×5=125(см³)-объём одного куба.
2)32×125=4000(см³)-объём всей коробки.

Answer 2

Finding the Volume of the Box

To find the volume of the box, we need to determine the length of one side of the square base of the box. Since the box is filled with 32 cubes and each cube has a side length of 5 cm, we can calculate the length of one side of the square base by dividing the total length of all the cubes by 4 (since there are 4 sides to a square).

The total length of all the cubes can be found by multiplying the number of cubes (32) by the side length of each cube (5 cm).

Let's calculate the length of one side of the square base:

32 cubes * 5 cm = 160 cm

To find the length of one side of the square base, we divide the total length of all the cubes by 4:

160 cm / 4 = 40 cm

Therefore, the length of one side of the square base is 40 cm.

Now, to find the volume of the box, we multiply the length of one side of the square base by itself and then multiply by the height of the box. Since the box is a cube, the height is equal to the length of one side of the square base.

Let's calculate the volume of the box:

40 cm * 40 cm * 40 cm = 64,000 cm³

Therefore, the volume of the box is 64,000 cm³.

Possible Dimensions of the Box

Since the volume of the box is 64,000 cm³, we can explore different combinations of dimensions that would result in this volume. Remember that the box is a cube, so all sides are equal in length.

Here are a few possible combinations of dimensions for the box:

1. Length = 40 cm, Width = 40 cm, Height = 40 cm 2. Length = 20 cm, Width = 20 cm, Height = 160 cm 3. Length = 10 cm, Width = 10 cm, Height = 640 cm 4. Length = 80 cm, Width = 80 cm, Height = 10 cm

These are just a few examples, and there are many other combinations of dimensions that would result in a volume of 64,000 cm³.