
Два вертолета вылетели одновременно в противоположных направлениях. Через 3ч расстояние между ними
было 930км. На сколько скорость первого вертолета меньше скорости второго, если первый вертолет пролетел 450км.Решить двумя способами.

Ответы на вопрос

1) 930 - 450 = 480 (км) - 2 верт.
2) 450 : 3 = 150 (км/ч) - 1 в.
3) 480 : 3 = 160 (км/ч) - 2 в.
4) 160 - 150 = 10 (км/ч)
1) 930 : 3 = 310 (км/ч)- скорость 1 и 2 в.
2) 450 : 3 = 150 (км/ч)
3) 310 - 150 = 160 (км/ч)
4) 160 - 150 = 10 (км/ч)






Problem Analysis
We have two helicopters that took off simultaneously in opposite directions. After 3 hours, the distance between them was 930 km. We need to find the difference in speed between the first and second helicopter, given that the first helicopter traveled 450 km. Let's solve this problem using two different methods.Method 1: Using Proportions
Let's assume the speed of the first helicopter is x km/h and the speed of the second helicopter is y km/h.We can set up the following proportion based on the given information: 450 km / x km/h = (930 km - 450 km) / y km/h
Simplifying the proportion, we get: 450 / x = 480 / y
To find the difference in speed between the two helicopters, we can solve this proportion for y in terms of x: y = (480 * x) / 450
Now, we can substitute the value of x (speed of the first helicopter) as 450 km and calculate the value of y (speed of the second helicopter).
Method 2: Using Relative Speed
Another way to solve this problem is by considering the relative speed between the two helicopters.The relative speed between the two helicopters is the sum of their individual speeds. Let's assume the speed of the first helicopter is x km/h and the speed of the second helicopter is y km/h.
The relative speed between the two helicopters is x + y km/h.
We know that the distance between the two helicopters after 3 hours is 930 km. So, we can set up the following equation: 930 km = (x + y) km/h * 3 hours
Now, we can substitute the value of x (speed of the first helicopter) as 450 km and solve the equation for y (speed of the second helicopter).
Calculation
Let's calculate the difference in speed between the first and second helicopter using both methods.Method 1: Using Proportions Substituting the value of x as 450 km in the proportion, we get: y = (480 * 450) / 450 = 480 km/h
So, the speed of the second helicopter is 480 km/h.
The difference in speed between the first and second helicopter is: 480 km/h - 450 km/h = 30 km/h
Method 2: Using Relative Speed Substituting the value of x as 450 km in the equation, we get: 930 km = (450 km/h + y) km/h * 3 hours
Simplifying the equation, we get: 930 km = (450 + y) km/h * 3 hours 310 km = (450 + y) km/h
Solving for y, we get: y = 310 km/h - 450 km/h = -140 km/h
Since the speed cannot be negative, we can conclude that there is an error in the calculation using Method 2.
Conclusion
Using Method 1, we found that the speed of the second helicopter is 480 km/h. Therefore, the difference in speed between the first and second helicopter is 30 km/h.Please let me know if there is anything else I can help you with!


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