Question

Два велосипедиста выехали одновременно навстречу друг другу и через 3 часа встретились. Какова скорость каждого, если известно, что первый проезжал за 1 час на 4 км больше второго, а вместе они проехали 108 км?

Answer 1

пусть скорость второго х, тогда

(х+4+х)*3=108

2х+4=108/3

2х=36-4

х=32/2

х=16км/ч скорость второго велосипедиста

16+4=20км/ч скоростьпервого велосипедиста

Answer 2

(х+4+х)*3=108

2х+4=108/3

2х=36-4

х=32/2

х=16(км/ч)- скорость 2-ого велосипедиста

16+4=20(км/ч)-скорость 1-ого велосипедиста

Answer 3

Problem Analysis

We have two cyclists who start simultaneously and meet after 3 hours. We need to find the speed of each cyclist given that the first cyclist travels 4 km more than the second cyclist in 1 hour, and together they cover a total distance of 108 km.

Solution

Let's assume the speed of the second cyclist is x km/h. Since the first cyclist travels 4 km more than the second cyclist in 1 hour, the speed of the first cyclist would be x + 4 km/h.

We know that the distance covered by each cyclist is equal to their speed multiplied by the time. Therefore, the distance covered by the first cyclist is (x + 4) * 1 km, and the distance covered by the second cyclist is x * 1 km.

After 3 hours, the total distance covered by both cyclists is 108 km. So we can set up the equation:

(x + 4) * 3 + x * 3 = 108

Simplifying the equation:

3x + 12 + 3x = 108

6x + 12 = 108

6x = 96

x = 16

Therefore, the speed of the second cyclist is 16 km/h, and the speed of the first cyclist is 16 + 4 = 20 km/h.

Answer

The speed of the first cyclist is 20 km/h, and the speed of the second cyclist is 16 km/h.