Question

Log2 корень из 27 / log2 27 помогите пожалуйста

Answer 1

Ну смотри log₃8 это 3log₃2, log₂27 это 3/log₃2, а 3^log₉25 это 3^log₃5 что будет = 5, а теперь умножаем первое на второе получаем 9, так как сокращаются логарифмы, теперь из 9 выч

Answer 2

Logarithm Calculation

To calculate log2(√27) / log2(27), we can simplify the expression using logarithmic properties.

First, let's simplify the numerator, log2(√27). The square root of 27 can be expressed as 27^(1/2). Using the property logb(x^y) = y * logb(x), we can rewrite the numerator as (1/2) * log2(27).

Next, let's simplify the denominator, log2(27).

According to the search results, I couldn't find a direct snippet that provides the value of log2(27). However, we can use the change of base formula to calculate it. The change of base formula states that logb(x) = logc(x) / logc(b), where c can be any base.

Let's use the natural logarithm (base e) to calculate log2(27). Applying the change of base formula, we have:

log2(27) = ln(27) / ln(2)

Now, let's substitute the numerator and denominator back into the original expression:

(1/2) * log2(27) / log2(27) = (1/2) * (ln(27) / ln(2)) / (ln(27) / ln(2))

Simplifying further, we can cancel out the common terms:

(1/2) * (ln(27) / ln(2)) / (ln(27) / ln(2)) = 1/2

Therefore, log2(√27) / log2(27) = 1/2.

Please let me know if there's anything else I can help you with!