Question

В 11 часов дня одновременно навстречу друг другу из двух пунктов выехали машины "Мазда" и"Форд"."Мазда" направлялась из пункта А в пункт В, а "Форд" ехал из пункта В в пункт А. Известно, что "Мазда" проезжала за 15 минут на 5 км. больше, чем "Форд". Через 180 минут после начала пути расстояние между машинами сократилось на 600 км. В этот момент "Мазда" сломалась, а "Форд", увеличив скорость на 15км./Ч., в 18 часов прибыл в пункт А. На каком расстоянии от пункта В сломалась " Мазда"

Answer 1

Если не видно 1 действие то
180:15=12

Answer 2

1) 180 мин:15 км = 12 км
2) 12 км*5 км = 60 км (на сколько Мазда проехала больше Форда)
3) (600 км - 60 км):2 = 270 км (S Форда)
4) 180 минут - это 3 часа. 270 км:3 = 90 км/ч (V Форда)
5) 90 км/ч + 15 км/ч = 105 км/ч (V Форда после увеличения V)
6) 18 ч - 11 ч - 3 ч = 4 ч (t Форда, после того, как сломалась Мазда)
7) 105 км/ч*4 ч = 420 км (S Форда после того, как сломалась Мазда)
8) 420 км + 270 км = 690 км (S от пункта А до пункта B)
9) 690 км - 330 км = 360 км (S от пункта B, до пункта, на котором сломалась Мазда)

Удачи ;)

Answer 3

Problem Analysis

We are given that two cars, a Mazda and a Ford, start simultaneously from two different points and travel towards each other. The Mazda is traveling from point A to point B, while the Ford is traveling from point B to point A. We are also given that the Mazda travels 5 km more than the Ford in 15 minutes. After 180 minutes, the distance between the two cars is reduced by 600 km. At that moment, the Mazda breaks down, and the Ford increases its speed by 15 km/h. We need to determine the distance from point B where the Mazda broke down.

Solution

Let's break down the problem step by step:

1. Let's assume the initial distance between point A and point B is D km. 2. The Mazda travels 5 km more than the Ford in 15 minutes. This means that the Mazda's speed is 5 km / 15 min = 1/3 km/min more than the Ford's speed. 3. Let's assume the Ford's speed is V km/min. Therefore, the Mazda's speed is V + 1/3 km/min. 4. After 180 minutes, the distance between the two cars is reduced by 600 km. This means that the Ford has covered 600 km more than the Mazda in 180 minutes. 5. Using the formula distance = speed × time, we can calculate the distance covered by the Ford in 180 minutes: (V + 1/3) km/min × 180 min. 6. We can also calculate the distance covered by the Mazda in 180 minutes: V km/min × 180 min. 7. The difference between the distances covered by the Ford and the Mazda is 600 km: (V + 1/3) km/min × 180 min - V km/min × 180 min = 600 km. 8. Simplifying the equation, we get: (V + 1/3 - V) km/min × 180 min = 600 km. 9. Solving for V, we find that V = 1 km/min. 10. Now, we know the Ford's speed is 1 km/min. We can calculate the initial distance between the two points using the information that the Mazda travels 5 km more than the Ford in 15 minutes. 11. The Mazda's speed is V + 1/3 = 1 + 1/3 = 4/3 km/min. 12. The Mazda travels 5 km more than the Ford in 15 minutes, so the distance traveled by the Mazda in 15 minutes is 5 km. 13. Using the formula distance = speed × time, we can calculate the initial distance between the two points: (4/3 km/min) × (15 min) = 20 km. 14. Therefore, the initial distance between point A and point B is 20 km. 15. The Mazda breaks down after 180 minutes, which is 3 hours. Therefore, the Mazda traveled (4/3 km/min) × (180 min) = 240 km before breaking down. 16. Since the Mazda broke down, the Ford continued to travel for another 3 hours at an increased speed of 15 km/h. 17. Converting 3 hours to minutes, we get 3 hours × 60 min/hour = 180 min. 18. The Ford's speed is 1 km/min, so its speed in km/h is 1 km/min × 60 min/hour = 60 km/h. 19. The Ford increases its speed by 15 km/h, so its new speed is 60 km/h + 15 km/h = 75 km/h. 20. Using the formula distance = speed × time, we can calculate the distance covered by the Ford in the additional 3 hours: (75 km/h) × (3 hours) = 225 km. 21. Therefore, the distance from point B where the Mazda broke down is 240 km + 225 km = 465 km.

Answer

The Mazda broke down at a distance of 465 km from point B.

Please let me know if I can help you with anything else.