Question

Всадники подъехали к заброшенной паромной переправе через Москву реку клязьму паром может перевести на один раз не более 10 центнеров Масса одного всадника 70 кг а масса одной лошади 420 кг лошадей нельзя оставить одних чтобы переправить по паром через реку достаточно одного человека всадники очень торопится за Какое наименьшее количество перегонов они вместе с лошадьми могут переправиться на противоположный берег Клязьмы

Answer 1

Перевозишь сначала двух лошадей и двух всадников потом также! 
2*420+140=980

Answer 2

Problem Analysis

The problem states that a group of riders has arrived at an abandoned ferry crossing over the Moscow River, specifically the Klyazma River. The ferry can carry a maximum of 10 centners (or 1000 kilograms) at a time. Each rider weighs 70 kilograms, and each horse weighs 420 kilograms. The riders cannot leave the horses alone. The goal is to determine the minimum number of crossings required for the entire group, including the horses, to cross to the opposite bank of the Klyazma River.

Solution

To find the minimum number of crossings required, we need to consider the weight capacity of the ferry and the total weight of the riders and horses.

Let's calculate the total weight of the riders and horses: - Total weight of one rider: 70 kilograms - Total weight of one horse: 420 kilograms

Since the riders cannot leave the horses alone, we need to consider the combined weight of each rider and their horse. This means the total weight for each rider-horse pair is 70 + 420 = 490 kilograms.

Now, let's calculate the maximum number of rider-horse pairs that can be transported in one crossing: - Maximum weight capacity of the ferry: 10 centners = 1000 kilograms - Weight of each rider-horse pair: 490 kilograms

To find the maximum number of rider-horse pairs that can be transported in one crossing, we divide the weight capacity of the ferry by the weight of each rider-horse pair: 1000 kilograms / 490 kilograms ≈ 2.04

Since we cannot have a fraction of a rider-horse pair, we round down to the nearest whole number. Therefore, the maximum number of rider-horse pairs that can be transported in one crossing is 2.

To find the minimum number of crossings required, we divide the total number of rider-horse pairs by the maximum number of pairs that can be transported in one crossing: Total number of rider-horse pairs / Maximum number of pairs per crossing

Let's calculate the total number of rider-horse pairs: - Number of riders: Not specified - Number of horses: Not specified

Since the number of riders and horses is not specified, we cannot determine the exact total number of rider-horse pairs. However, we can provide a general formula to calculate the minimum number of crossings required based on the number of rider-horse pairs.

Let's denote the number of rider-horse pairs as "n". The minimum number of crossings required can be calculated using the formula: Minimum number of crossings = ceil(n / 2)

The ceil function rounds up to the nearest whole number.

Answer

Based on the information provided, we can determine the minimum number of crossings required to transport the riders and horses across the Klyazma River. However, since the number of riders and horses is not specified, we cannot provide an exact answer. We can only provide a general formula to calculate the minimum number of crossings based on the number of rider-horse pairs.

To calculate the minimum number of crossings, use the formula: Minimum number of crossings = ceil(n / 2)

Where "n" represents the total number of rider-horse pairs.

Please provide the number of riders and horses so that we can calculate the minimum number of crossings more accurately.